No Loops, No Problem: Mastering Digit Reversal in C++

Problem Description:

No Loops, No Problem: Mastering Digit Reversal in C++

Write a C++ program that takes a three-digit number as input and prints the

number with its digits reversed. For example, if the input is 123, the output

should be 321.

Task:

1. Declare a variable to store the three-digit number.

2. Use arithmetic operations (division and modulus) to extract the digits of

the number.

3. Rearrange and print the digits in reverse order.

Input Format:

● Take three digit number from user e.g 123

Output Format:

● The number with its digits reversed. E.g 321

Solution:

Code:

#include <iostream>

using namespace std;

int main(){

cout<<"Rearrange and Print the Digits in Reverse Order"<<endl;

cout<<"-----------------------------------------------"<<endl;

int num;

cout<<"Enter Number for Reverse: "<<endl;

cin>>num;

int last_number=num%10;

int middle_number=(num/10)%10;

int first_number=num/100;

cout<<last_number<<middle_number<<first_number;

    return 0;

}

Output:

Thanks......

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